### Q.2:- The position-time (x-t) graphs for two children A and B returning from their school O to their homes P and Q respectively are shown in Fig. 3.19. Choose the correct entries in the brackets below;

(a) (A/B) lives closer to the school than (B/A)

(b) (A/B) starts from the school earlier than (B/A)

(c) (A/B) walks faster than (B/A)

(d) A and B reach home at the (same/different) time

(e) (A/B) overtakes (B/A) on the road (once/twice).

**Answer:-**(a) As

*OP < OQ*,*A*lives closer to the school than*B*.(b) For

*x*= 0,*t*= 0 for*A*; while*t*has some finite value for*B*. Therefore,*A*starts from the school earlier than*B*.(c) Since the velocity is equal to slope of

*x-t*graph in case of uniform motion and slope of*x-t*graph for*B*is greater that that for*A*=, hence*B*walks faster than*A*.(d) It is clear from the given graph that both *A* and *B* reach their respective homes at the same time.

(e) *B* moves later than *A* and his/her speed is greater than that of *A*. From the graph, it is clear that *B* overtakes *A* only once on the road.