### Q.11:- The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the area and volume of the sheet to correct significant figures.

**Answer:-**

Given that,

length, *l* = 4.234 m

breadth,b = *1*.005 m

thickness, *t* = 2.01 cm = 2.01 × 10^{-2} m

Area of the sheet = 2 (*l* × *0* + *b* × *t* + *t* × *l*) = 2 (4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)

= 2 (4.3604739) = 8.7209478 m2

As area can contain a maximum of three significant digits, therefore, rounding off, we get

Area = 8.72 m^{2}

Also, volume = *l* × *b* × *t*

*V* = 4.234 × 1.005 × 0.0201 = 0.0855289 = 0.0855 m^{3} (Significant Figures = 3)