A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s–1? | Learn NCERT solution | Education portal Class 11 Physics | Study online Unit-15 Waves



Q.2:- A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s–1? (g= 9.8 m s–2)

 

 

Answer:-



Height of the tower, s = 300 m
Initial velocity of the stone, u = 0
Acceleration, a = g = 9.8 m/s2
Speed of sound in air = 340 m/s
The time (t1) taken by the stone to strike the water in the pond can be calculated using the second equation of motion, as:
s = ut1 + 1/2 gt12
300 = 0 + 1/2 × 9.8 × t12
t1 = √300 × 2/9.8  = 7.82 s
Time taken by the sound to reach the top of the tower, t2 = 300/340 = 0.88 s
Therefore, the time after which splash is heard,  t = t1 + t2
= 7.82 + 0.88 = 8.7 s.