Q.11:- Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω.
(i) Two resistors in parallel
Two 6 Ω resistors are connected in parallel. Their equivalent resistance will be
The third 6 Ω resistor is in series with 3 Ω. Hence, the net resistance of the circuit is 6 Ω + 3 Ω = 9 Ω.
(ii) Two resistors in series
Here Rs=6+6=12 Ω let third resistance R3=6 Ω
Two 6 Ω resistors are in series. Their equivalent resistance will be the sum
∴ the total resistance is 4 Ω.
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