Which one of the following will have largest number of atoms? (i) 1 g Au (s) (ii) 1 g Na (s) (iii) 1 g Li (s) (iv) 1 g of Cl2 (g)



Q.28:- Which one of the following will have largest number of atoms?
(i) 1 g Au (s)
(ii) 1 g Na (s)
(iii) 1 g Li (s)
(iv) 1 g of Cl2 (g)

 

 

Answer:-



(i) 1 g Au = 1/197 mol = 1/197×6.022×1023 atoms
(ii) 1 g Na = 1/23 mol = 1/23×6.022×1023 atoms
(iii) 1 g Li = 1/7 mol = 1/7×6.022×1023 atoms
(iv) 1 g Cl= 1/71 mol = 1/71×6.022×1023 atoms
Thus, 1 g of Li has the largest number of atoms.