The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm





Q.50:- The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calcualte the frequency of each transition and energy difference between two excited states.

 

 

Answer:-
λ1 = 589 nm = 589×10-9 m
∴ ν1 = c/λ1 = 3.0×10ms-1/589×10-9 m = 5.093×1014 s-1
λ2 = 589.6 nm = 589.6×10-9 m
∴ ν2 = c/λ2 = 3.0×10ms-1/589.6×10-9 m = 5.088×1014 s-1
ΔE = E2 – E= h(ν ν1) = (6.626×10-34 Js)×(5.093-5.088)×1014 s-1 = 3.31×10-22 J