In Exercise 14.9, let us take the position of mass when the spring is unstreched as x = 0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is (a) at the mean position, (b) at the maximum stretched position, and (c) at the maximum compressed position. In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase? | Learn NCERT solution | Education portal Class 11 Physics | Study online Unit-14 Oscillations



Q.10:- In Exercise 14.9, let us take the position of mass when the spring is unstreched as x = 0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is
(a) at the mean position,
(b) at the maximum stretched position, and
(c) at the maximum compressed position.
In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase?

 

 

Answer:-

Distance travelled by the mass sideways, a = 2.0 cm
Angular frequency of oscillation:



(a) As time is noted from the mean position, hence using
x = a sin ω t, we have x = 2 sin 20 t
 
(b) At maximum stretched position, the body is at the extreme right position, with an intial phase of π/2 rad. Then,
(c) At maximum compressed position, the body is at left position, with an intial phase of 3 π/2 rad. Then,
The functions neither differ in amplitude nor in frequency. They differ in intial phase.