Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: N2(g) + H2(g) → 2NH3(g)



Q.24:- Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2(g) + H2(g) → 2NH3(g)
(i) Calculate the mass of ammonia produced if 2.00×103g dinitrogen reacts with 1.00×103g of dihydrogen.
(ii) Will any of the two reactants remain unreacted?
(iii) If yes, which one and what would be its mass?

 

Answer:-

1 mole of dinitrogen (28g) reacts with 3 mole of dihydrogen (6g) to give 2 mole of ammonia (34g).



∴ 2000 g of Nwill react with H= 6/28 ×200g = 428.6g. Thus, here Nis the limiting reagent while His in excess.
28g of N2 produce 34g of NH3.
∴2000g of N2 will produce = 34/28×2000g = 2428.57 g of NH3.
(ii) N2 is the limiting reagent and H2 is the excess reagent. Hence, H2 will remain unreacted.

(iii) Mass of dihydrogen left unreacted = 1000g – 428.6g = 571.4 g