Q.37:- The diameter of zinc atom is 2.6 Å.Calculate (a) radius of zinc atom in pm and (b)number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.
(a) Radius of zinc atom = 2.6Å/2 = 1.3Å = 1.3×10-10 m = 130×10-12 pm
(b) Given length = 1.6 cm = 1.6×10-2 m
Diameter of one atom = 2.6 Å = 2.6×10-10 m
∴ No. of atoms present along the length = 1.6×10-2/2.6×10-10 = 6.154×107