If the density of methanol is 0.793 kg L-1 , what is its volume needed for making 2.5 L of its 0.25 M solution?



Q.12:- If the density of methanol is 0.793 kg L-1 , what is its volume needed for making 2.5 L of its 0.25 M solution?

Answer:-



Molar mass of methanol (CH3OH) = (1×12)+(4×1)+(1×16) = 32 g mol-1 = 0.032 kg mol-1
Molarity of the solution = 0.793/0.032 = 24.78 mol L-1 

Applying, M1V1 (Given Solution) = M2V(Solution to be prepared)
24.78×V= 0.25×2.5 L
V1= 0.02522 L = 25.22 mL