What is the concentration of sugar (C12H22O11) in mol L-1 if its 20 g are dissolved in enough water to make a final volume up to 2L?



Q.11:- What is the concentration of sugar (C12H22O11) in mol L-1  if its 20 g are dissolved in enough water to make a final volume up to 2L?

 

 

Answer:-



Molar mass of sugar (C12H22O11) = (12×12)+(1×22)+(11×16) = 342 g mol-1
No. of moles in 20g of sugar = 20/342 = 0.0585 mole

Volume of Solution = 2L (given)
Molar concentration = Moles of solute/Volume of solution in L = 0.0585mol/2L = 0.0293 mol L-1 = 0.0293 M