Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Q. Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

 

Answer:-



Given Charge (Q) =96000C
Time (t)=1hr=60×60=3600s
Potential difference V=50volts
Now we know that H= VIt
So we have to calculate I first
As I=Q/t
∴ I=96000/3600=80/3 A
b


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