A body describes simple harmonic motion with amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm, (c) 0 cm. | Learn NCERT solution | Education portal Class 11 Physics | Study online Unit-14 Oscillations



Q.24:- A body describes simple harmonic motion with amplitude of 5 cm and a period of 0.2 s. Find the acceleration and velocity of the body when the displacement is (a) 5 cm, (b) 3 cm, (c) 0 cm.

 

 

Answer:-

r = 5 cm = 0.05 m
T = 0.2 s
ω = 2π/T = 2π/0.2 = 10 π rad/s

When displacement is y, then acceleration, A = -ω2 y



Case (a) When y = 5cm = 0.05 m
A = -(10π)2 × 0.05 = -5π2 m/s2
Case (b) When y = 3 cm = 0.03 m
A = -(10π)2 × 0.03 = -3π2 m/s2
Case (c) When y = 0
A = -(10π)2 × 0 = 0