An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

Q. 14 :- An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size. 

 

Answer:-

Radius of curvature, R = + 30 cm
Focal length, f = R/2 = + 30/2 cm = + 15 cm
Object-distance, u = – 20 cm
Height of object
h1′= 5 cm
Image-distance, v = ? Height of image h2′= ?

1 1 1

+
=
v u f
1 1 1

+
=
v − 20 + 15
1 1 1

=
+
v 15 20
1 4 + 3 7

=
=
v 60 60
60
v =
= 8.57 cm
7

The image is formed behind the mirror at a distance of 8.6 cm 



h2 − v
m =
=
h1 u
h2 8.57
=> =
=
5 cm 20
8.57 × 5 cm
= h2 =
20
Height (Size )

of Image

= h2 = 2.175 cm

Thus, a 2.175 cm high, virtual and erect image is formed



TutionTeacher: Know free answers of your school textbook. You can find the correct answer of your School textbook question here. This education portal will help in getting the NCERT solutions for your exams. Here you will get the complete question answer and solution of your textbook for your better education. Your can also ask for online study and assignment help from menu. Online test series will also help you how to learn and achive better marks in your school or collage.