## An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source

### Q. An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

Resistance of electric lamp (R1) = 100 Ω
Resistance of toaster (R2) = 50 Ω
Resistance of water filter (R3) = 500 Ω
Potential difference of the source, V = 220 V
Since all the resistance are in parallel then the equivalent resistance R of the circuit will be All the three given appliances are drawing 7.04 A of current.
Therefore, current drawn by an electric iron connected to the same source of potential 220 V = 7.04 A
Let   Rʹ be the resistance of the electric iron. According to Ohm’s law,
Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.