### Q. An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

**Answer:-**

Resistance of electric lamp (R

_{1}) = 100 ΩResistance of toaster (R

_{2}) = 50 ΩResistance of water filter (R

_{3}) = 500 ΩPotential difference of the source,

*V*= 220 VSince all the resistance are in parallel then the equivalent resistance

*R*of the circuit will beAll the three given appliances are drawing 7.04 A of current.

Therefore, current drawn by an electric iron connected to the same source of potential 220 V = 7.04 A

Let Rʹ be the resistance of the electric iron. According to Ohm’s law,

Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.