An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

Q. An electric iron of resistance 20 Ω takes a current of 5 A. Calculate the heat developed in 30 s.

 

Answer:-



Given that Resistance(R) = 20 Ω, Electric current (I)= 5 A and time(t)= 30 s
Now we know that H= I2Rt
                                = 5×5×20×30
                                = 15000J=1.5×104J
∴ The heat developed in 30s is 1.5×104J


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