The acceleration due to gravity on the surface of moon is 1.7 ms–2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? | Learn NCERT solution | Education portal Class 11 Physics | Study online Unit-14 Oscillations



Q.15:- The acceleration due to gravity on the surface of moon is 1.7 ms–2. What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 ms–2)

 

 

Answer:-

Acceleration due to gravity on the surface of moon,g‘ = 1.7 m s–2

Acceleration due to gravity on the surface of earth, g = 9.8 m s–2
Time period of a simple pendulum on earth, T = 3.5 s



Hence, the time period of the simple pendulum on the surface of moon is 8.4 s.