Q.:- A train is travelling at a speed of 90 kmh-1. Brakes are applied so as to produce a uniform acceleration of -0.5 ms-2. Find how far the train will go before it is brought to rest?
Here, initial speed, u = 90 kmh-1 = 90 x(5/18) = 25 ms-1
Acceleration, a = – 0.5 ms-2
Train brought to rest, so final speed, v = 0
From third equation of motion, v2 = u2 + 2as
0 = (25)2 + 2 x 0.5 x s
0 = 625 – s
s = 625 m
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