A train is travelling at a speed of 90 kmh-1. Brakes are applied so as to produce a uniform acceleration of -0.5 ms-2. Find how far the train will go before it is brought to rest?



Q.:- A train is travelling at a speed of 90 kmh-1. Brakes are applied so as to produce a uniform acceleration of -0.5 ms-2. Find how far the train will go before it is brought to rest?

 

Answer:-

Here, initial speed, u = 90 kmh-1 = 90 x(5/18)  = 25 ms-1
Acceleration, a = – 0.5 ms-2
Train brought to rest, so final speed, v = 0
From third equation of motion, v2 = u2 + 2as
0 = (25)2 + 2 x 0.5 x s
0 = 625 – s
s = 625 m



TutionTeacher: Know free answers of your school textbook. You can find the correct answer of your School textbook question here. This education portal will help in getting the NCERT solutions for your exams. Here you will get the complete question answer and solution of your textbook for your better education. Your can also ask for online study and assignment help from menu. Online test series will also help you how to learn and achive better marks in your school or collage.