A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

Q.:- A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

 

Answer:-

Figure ABCD is a square field of side 10 m.
Time for one round = 40 s
Total time = 2 min 20 s
= (2 x 60 + 20) s = 140 s



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Number of round completed

If farmer starts from A, it will complete 3 rounds A
at A. In the last 0.5 round starting from A, he will finish at C.



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