Q.7:- A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.
Mass of the body, m = 5 kg
The given situation can be represented as follows:
The resultant of two forces is given as:
θ is the angle made by R with the force of 8 N
∴ θ = tan-1(-6/8) = -36.870
The negative sign indicates that θ is in the clockwise direction with respect to the force of magnitude 8 N.
As per Newton’s second law of motion, the acceleration (a) of the body is given as:
F = ma
∴ a = F / m = 10 / 5 = 2 ms-2