A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

Q.9:- A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

 

Answer:-



There is no current division occurring in a series circuit. Current flow through the component is the same.
Resistances are connected in series. Hence, the sum of the resistances will give the value of R= 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω
Potential difference, V = 9 V
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∴ the current that would flow through the 12 Ω resistor will be 0.671 A.


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